Nuclear physics 100% energy theorem. (pdf document) free file download at fliiby.com

"Welcome to my web site! The purpose of this site is to show off unpublished exciting Nuclear Physics and then an article on Time and a basic article on Weather Forecasting Nuclear Physics Time Weather Forecasting Please comment alanbret@hotmail.com Nuclear Physics Cold Fusion in a pile and radioactive pathways. Possibilities in Nuclear physics resulting from the 1+1=2 Equation. That is a result from the Particle-wave theory. The Neutron could be a Proton plus electron who is to say that electrons don’t fall into the nucleus. Then Hydrogen would be a nucleus of two protons and one electron. When heated to the extreme the electron would go leaving two protons Helium (atomic fusion) then when it cooled down the nucleus capturing another electron reverting to hydrogen. Uranium has a large number of these neutrons who might be protons with a electron bound. When the electrons go then this leaves too many protons--fission. One could transform one element into another by adding electrons to the nucleus or taking them away at high temperature. Positrons would be a useful tool too. W a v e P a r t i c l e T h e o r y A d v a n t a g e s : 1) Change one element into Another (Gold, Platinum). 2) 10X bigger Atomic bomb or nuclear energy with the 100% mass to energy conversion. 3) New radioactive pathways and manufacturing isotopes. 4) A Good way of treating Radioactive waste. 5) A understanding of Radioactivity influencing the particles of the nucleus and decays even to the smallest particle. 6) A New understanding of the nucleus and binding 1+1 that can be generalized to all atoms. Alan Brett alanbret@hotmail.com Wave-Particle Theory Abstract: A reaction in what all mass is converted (particle disintegrates) to energy. Caused by gamma radiation. Theory says one can force proton or electron decay using gamma radiation at the deBroglie wavelength of the particle. Smaller particles, and this is important for particle physicists, will decay if hit by lower frequencies than gamma. Done mathematically simply using Schrodingers wave equations FINDING a mathematical result that the above will only occur at a specific frequency of incoming photon—the deBroglie wavelength of the particle. One would have to account for Amplitude too and Potential and Kinetic energy. Abstract: (continued) Page two. Of interest for high theory is one can redo the math treatment again for any energy E1 + any energy E2 producing any energy E3 . Eone + Etwo = Ethree (as time continues) the math solves one variable and produces Eone=Etwo producing a double Ethree. 1 + 1 = 2 (bound) One thinks here of the neutron being so close in energy to the Proton and the binding that occurs in the nucleus. Plus radioactivity due to a asymmetric binding. And isotopes. And the smallest of particles and there binding. Also of interest to Nuclear Physicists is the binding of the hydrogen nucleus in fusion. And asymmetric binding in Uranium. Section 1 Introduction The before and after ENERGY conditions are placed in the Schrodinger equation to give the before and after WAVES. See fig. 1 These waves are equal at the continuity point between before and after See fig. 2 and this makes the waves equal at this point. This solves the variable in the initial conditions. This solves the problem. Page 3. Mathematicle Treatment Section 2 Energy Conservation For fig. 1 page 1 Ebefore = Eafter Or from the figure a photon hits a particle (in a potential) and produces photons. This is(1) hμ + mc2 + V = xhμ photon + particle + potential energy = a unknown number of photons Eafter = xhμ this is x in units of (hμ) This is any number of photons out because of additivity of Energy. But is that way to obtain a chain reaction. hμ = energy of photon in mc2 = mass energy of particle V = potential energy the particle is in x =variable that determines Eafter Page 4 These energies are placed in the wave equations by Schrodinger, the time dependant ones, then with time I can describe the before and after conditions as waves that are continuous at the point between before and after. Section 3 Initial Conditions Ebefore = hμ + mc2 + V Ψ = ℮ -iEt/ħ Solution of the time dependant Schrodinger equation. Placing the energy equation in the above equation. We obtain. (2) Ψinitial = ℮-i(mc²+V)t/ħ + ℮-ihμt/ħ This is the addition of a particle wave and an electromagnetic wave ie. Absorption of the photon by the particle. Folowing is the result of that absorption— Section 4 Final Conditions Efinal = xhμ So the wave out is-Φfinal = x℮-ihμt/ħ = x (photon of energy hμ) = a chain reaction—but it must be mentioned that their is the superposition of waves principle so long as they all add up to the above. So this may be anything out. Page 5 Section 5 Continuity with time (4) Ψinitial= Φfinal (continuity condition) At some point in time the wave before equals the wave after. The Calculations Section 6 Solve for hµ to obtain the frequency of the incident photon (5) Ψinitial= ℮-i(mc²+V)t/ħ + ℮-ihμt/ħ = x℮-ihμt/Ћ= Φfinal Next we solve this for x Page 6 Solve for x--(x-1) = ℮[-i(mc²+V)t/ħ + ihμt/ħ] Useing now equation 1 , Page 3 The energy conservation equation— Where (x-1) =(mc2 + V)/hμ Equating these two at (x-1) and ln both sides to get rid of exp. ln {(mc2 + V)/hμ} = [mc2 + V – hμ ](-it/ħ) (6) hμ = mc2 + V +( iħ/t) ( ln{ [mc2 + V]/ hμ}) Wave Particle Equation The simplest solution is— (7) hμ =mc2 +V This gives the initial frequency of photon needed to decay the particle. Page 7 Section 7 Conclusions Here is the frequency of the photon needed to decay a particle. hμ = mc2 + V Where m is the rest mass (relativistic) and V is the potential energy of the particle. This result ties in with de Broglie particle waves, De Broglie gives λdeBroglie=h/p = h/mc (P=E/c) (8) so hμdeBroglie= mc2 like the top of the page from our calculations, is there in established theory. We must remember the deBroglie wave of a charged particle is also an electromagnetic wave. For conservation of spin and charge small particles might be produced. Page 8 Section 8 The neutron Like mentioned earlier one can generalize the initial equations to— (9) E1 + E2 = E3 Our treatment That isE1 + E2 = xE1 Solution x = 2 And E1=E2 (10) E1 + E1 =2E1 This is then a law that all particles at the quantum level will obey. So two protons OF THE SAME ENERGY combine. Two electrons OF THE SAME ENERGY bond in one orbit. The neutron is more or less THE SAME ENERGY as the Proton. Here is a peek at the structure of the nucleus with this binding occurring and radioactivity relieving the energy differences. And is interesting for isotopes being out of balance of 1+1=2. Home Home Nuclear Physics Weather forecasting TIME Simply. What is time? hµ =E=h/T(Light How about waves the best oscillators ). T=(h/E)=( 1/1)=1 second when E=h=10-22J This is critical to understand that one second (arbitrarily defined) is defined as when the Energy is h. E=h at one second (Energy =h at one second). So time is lots of h’s. Time of 1 second means one h value. Conversely h=the energy of one second in all the equations featuring h. In a clock time increases as Energy decreases (spring or battery). For time to decrease Energy would increase. T=h/E and (ò)T=(ò)(h/E) where ò is delta or change in Energy, Time ect. Watch now because those deltas introduce time being able to go backward or forward. Some examples: The sun would be losing energy --time would go forwards. The earth would be gaining energy--time would go backwards. People lose energy--time goes forwards. Space does nothing--time stops. A black hole absorbs energy--time would go backwards. A Quaser or super nova lose energy very fast--- they jump to the future very fast. We can say in the equations that this E (and time associated) is dependant on Enthalpy and Entropy and Temperature. (ò)E=(ò)H-Temp(ò)S just for info. PAST AFFECTING THE FUTURE If one goes through 3 green lights in ones car one can predict the next will most probable be a red. If on the roulette wheel black came up 3 times the next will probably be red. One has to take history into account as causing FATE or a predictable future. Current probability and chance math doesn't take history into account. Home Nuclear Physics Time. Weather Forecasting. From the basic ideas that there are are three Low belts one at the equator one at each tropic and ignoring the high belts as resulting from the lowbelts I concentrate then on these lowbelts simply interacting with each other simply the maths of interfering sine waves. Sine waves are described by there wavelength (in days) as each low pressure system goes across. This is taken from the size of the oceanic crossing this is different (seen on map of the continents) for 1) Tropic lowbelts. 2) Equator lowbelt. The bigger time over the ocean produces the bigger low cell. These two belts Tropic and Equator interact—there separate equations added together. THIS GIVES THE WEATHER. Further added to the seasons curve for the year. Weather Forecasting— Temperature and Pressure— The math! seasons The Math for the seasons is Asin[{(y/365)x360}-90] A=Amplitude Y=Day of the year starting 1st January. our low belt The Math for our low belt is 5days(this would have to be taken from Temperature charts. This is the size of Low cell estimated from Length of ocean Crossing. Bsin[(360xY/5)+ф] B=Amplitude Y=Day of the year Ф=initial calibration Equater low belt Wavelength determined by Size of ocean crossing at The equator relative to Size of crossing at The tropics. The Math for the Equator low belt is Csin([360xY/wavelength]+и) C=Amplitude Y=day of year И=initial conditions These three equations added up will forecast the weather once initialized all this does is predict the basic oscillations and can predict severe weather coming a month away. It would be best to write this into a computer program. And can be tested by predicting past Temperatures/Pressures. Email you are welcome to respond. alanbret@hotmail.com ..."

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